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Merge branch 'bugfix/fix_heap_memory_corruption_v4.3' into 'release/v4.3'
Heap: Fix a possible bug in the TLSF allocator (backport v4.3) See merge request espressif/esp-idf!16508
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commit
ade22c9072
@ -801,10 +801,14 @@ void* tlsf_memalign_offs(tlsf_t tlsf, size_t align, size_t size, size_t data_off
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*/
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const size_t size_with_gap = adjust_request_size(adjust + align + gap_minimum - off_adjust, align);
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/*
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** If alignment is less than or equals base alignment, we're done.
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** If we requested 0 bytes, return null, as tlsf_malloc(0) does.
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*/
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/*
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** If alignment is less than or equal to base alignment, we're done, because
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** we are guaranteed that the size is at least sizeof(block_header_t), enough
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** to store next blocks' metadata. Plus, all pointers allocated will all be
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** aligned on a 4-byte bound, so ptr + data_offset will also have this
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** alignment constraint. Thus, the gap is not required.
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** If we requested 0 bytes, return null, as tlsf_malloc(0) does.
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*/
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const size_t aligned_size = (adjust && align > ALIGN_SIZE) ? size_with_gap : adjust;
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block_header_t* block = block_locate_free(control, aligned_size);
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@ -820,10 +824,12 @@ void* tlsf_memalign_offs(tlsf_t tlsf, size_t align, size_t size, size_t data_off
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tlsf_cast(tlsfptr_t, aligned) - tlsf_cast(tlsfptr_t, ptr));
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/*
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** If gap size is too small or if there is not gap but we need one,
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** If gap size is too small or if there is no gap but we need one,
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** offset to next aligned boundary.
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** NOTE: No need for a gap if the alignment required is less than or is
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** equal to ALIGN_SIZE.
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*/
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if ((gap && gap < gap_minimum) || (!gap && off_adjust))
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if ((gap && gap < gap_minimum) || (!gap && off_adjust && align > ALIGN_SIZE))
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{
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const size_t gap_remain = gap_minimum - gap;
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const size_t offset = tlsf_max(gap_remain, align);
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@ -484,6 +484,22 @@ TEST_CASE("multi_heap aligned allocations", "[multi_heap]")
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}
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}
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/* Check that TLSF doesn't allocate a memory space smaller than required.
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* In any case, TLSF will write data in the previous block than the one
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* allocated. Thus, we should try to get/allocate this previous block. If
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* the poisoned filled pattern has beeen overwritten by TLSF, then this
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* previous block will trigger an exception.
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* More info on this bug in !16296. */
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const size_t size = 50; /* TLSF will round the size up */
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uint8_t *buf1 = (uint8_t *)multi_heap_aligned_alloc(heap, size, 4);
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uint8_t *buf2 = (uint8_t *)multi_heap_aligned_alloc(heap, size, 4);
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multi_heap_free(heap, buf1);
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/* By specifying a size equal of the gap between buf1 and buf2. We are
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* trying to force TLSF to allocate two consecutive blocks. */
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buf1 = (uint8_t *)multi_heap_aligned_alloc(heap, buf2 - buf1, 4);
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multi_heap_free(heap, buf2);
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printf("[ALIGNED_ALLOC] heap_size after: %d \n", multi_heap_free_size(heap));
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REQUIRE((old_size - multi_heap_free_size(heap)) <= leakage);
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}
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